Question

mass of 112^3 of CH4 gas at STP IS

Answer 1

If question is mass of 112^3 L of CH4 gas then see solution below :

Since 1 molecular mass of CH4 occupy 22.4L.
Means 20 g of CH4 occupy 22.4L.

Then 20/22.4g of CH4 occupy 1L.

So 20/22.4* 112^3 g of CH4 occupy 112^3 L.

= 20/22.4*112*112*112

=1254400 g.

Hope it's helpful to u.