Question

Mass of 112 mL of a certain gas is 0.22 g at STP . How many molecules are there in the sample of gas ? what is the molar nass of the gas​

Answer 1

Explanation:

At STP,

P = 105 Pa

T= 273K

R = 8.31 J/K

Now, 1ml = 10-6 m3

From ideal gas equation,

Given,

Mass of 0.005 moles of gas X = 0.22 g

Therefore,

Mass of 1mole of gas X = 0.22 / 0.005

= 44g

Hence, the relative molecular mass of Gas X = 44g