Chemistry, asked by rutujadere1011, 1 month ago

Mass of 112 mL of a certain gas is 0.22 g at STP. How many molecules are there in the
sample of gas ? What is the molar mass of the gas ?​

Answers

Answered by rsagnik437
99

Answer :-

→ Number of molecules are 3.011 × 10²¹ .

→ Molar mass of the gas is 44 g/mol .

Explanation :-

We have :-

• Volume of the gas = 112 mL = 0.112 L

Mass = 0.22 g

________________________________

At STP condition :-

• Pressure (P) = 1 atm

• Temperature (T) = 273 K

Firstly, let's calculate the number of moles of the gas using Ideal Gas equation :-

PV = nRT

⇒ 1 × 0.112 = n × 0.0821 × 273

⇒ 0.112 = 22.4n

⇒ n = 0.112/22.4

⇒ n = 0.005

________________________________

Number of molecules :-

= No of moles × Avogadro Number

= 0.005 × 6.022 × 10²³

= 0.03011 × 10²³

= 3.011 × 10²¹ molecules

Molar mass :-

= Given Mass/No of moles

= 0.22/0.005

= 220/5

= 44 g/mol

Answered by MяMαgıcıαη
110

\red{\bigstar} G I V E N

\:

◈ Mass of 112 ml of a certain gas is 0.22 g at STP

\:

\blue{\bigstar} T OF I N D

\:

◈ How many molecules are there in the sample of gas?

◈ What is the molar mass of the gas?

\:

\purple{\bigstar} S O L U T I O N

\:

Converting units of volume from ml to l ::

\:

\sf \quad \dashrightarrow \quad 1\:ml = 1000\:l

\\ \sf \quad \dashrightarrow \quad 112\:ml = \dfrac{112}{1000}\:l

\\ \sf \quad \dashrightarrow \quad \purple{112\:ml = 0.112\:l}

\:

Finding number of moles ::

\:

\underline{\sf{\bigstar\:As\:we\:know\:that\:::}}

\:

\underline{\boxed{\sf{Number\:of\:moles = \dfrac{Volume}{Volume\:at\:STP}}}}

\:

Putting all known values ::

\:

\sf \quad \dashrightarrow\quad Number\:of\:moles = \dfrac{0.112}{22.4}

\\ \quad \sf \dashrightarrow\quad\green{Number\:of\:moles = 0.005\:mol}

\:

Finding number of molecules ::

\:

\underline{\boxed{\sf{1\:mol = 6.022\:\times\:10^{23}\:molecules }}}

\\ \small \sf \dashrightarrow\: 0.005\:mol = 0.005\:\times\:6.022\:\times\:10^{23}\:molecules

\\ \small \sf \dashrightarrow\: 0.005\:mol = 0.03011\:\times\:10^{23}\:molecules

\\ \small \sf \dashrightarrow\:\orange{ Number\:of\:molecules = 3.011\:\times\:10^{21}}

\:

Finding molar mass ::

\:

\underline{\sf{\bigstar\:As\:we\:know\:that\:::}}

\:

\underline{\boxed{\sf{Number\:of\:moles = \dfrac{Given\:Mass}{Molar\:Mass}}}}

\:

Putting all known values ::

\:

\sf \quad\dashrightarrow\quad 0.005 = \dfrac{0.22}{Molar\:Mass}

\\ \sf \quad\dashrightarrow\quad Molar\:Mass = \dfrac{0.22}{0.005}

\\ \sf \quad\dashrightarrow\quad \pink{Molar\:Mass = 44\:g}

\:

\red{\bigstar} H E N C E

\:

»» Number of molecules = 3.011 × 10²¹

»» Molar Mass = 44 g

\:

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