Question

Mass of 3.011x10^22 atoms of Ca

Answer 1

Moles= N/Na = (3.011 x 10^22)/(6.022 x 10^23)= 1/20 moles

Mass= Atomic mass x Mole

       = 40 x 1/20 = 2g

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Answer 2

Mass of $3.011\times 10^{22}$ atoms of Ca is 2 g

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given atoms}}{\text {avogadro's number}}=\frac{3.011\times 10^{22}}{6.023\times 10^{23}}=0.05moles$

1 mole of calcium weigh = 40 g

Thus 0.05 moles of calcium will weigh =$\frac{40}{1}\times 0.05=2g$

Mass of $3.011\times 10^{22}$ atoms of Ca is 2 g

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