Physics, asked by XxOollMrSANJUlloOxX, 6 days ago

mass of 50 g of a certain metal at 150°C is immersed in 100 g of water at 11°C. The final temperature is 20°C. Calculate the specific heat capacity of the metal. Assume that the specific heat capacity of water is :- \rm \: 4.2 \: Joule \: g^{ - 1} \: K ^{ - 1}4.2Jouleg−1K−1​

Answers

Answered by swaransingh49957
6

Answer:

gud mrng:)

here izz ur answer

Mass if the solid , m

Mass if the solid , m s=50g

=50gInitial temperature of the solid, t

=50gInitial temperature of the solid, t s=1500

=50gInitial temperature of the solid, t s=1500C=150+273=423k

=50gInitial temperature of the solid, t s=1500C=150+273=423kMass of water, m

=50gInitial temperature of the solid, t s=1500C=150+273=423kMass of water, m w=100g

=100gTemperature of the water, tw=110C=11+273=293k

C=11+273=293kAccording to principle of calorie meter,

C=11+273=293kAccording to principle of calorie meter,Heat gained by water =Heat lost by the solid

C=11+273=293kAccording to principle of calorie meter,Heat gained by water =Heat lost by the solid ∴mw

Cw

Cw(t−t w)=m s

Cs (ts−t)⇒100×4.2(293−284)=50×Cs×(423−293)⇒3780=6500Cs

∴Cs =0.582J/gk

Answered by xxbadmaash01x
1

Answer:

in 100 g of water at 11°C. The final temperature is 20°C. Calculate the specific heat capacity of the metal. Assume that the specific heat capacity of water is :- \rm \: 4.2 \: Joule \: g^{ - 1} \: K ^{ - 1}4.2Jouleg−1K−1

Explanation:

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