mass of 50 g of a certain metal at 150°C is immersed in 100 g of water at 11°C. The final temperature is 20°C. Calculate the specific heat capacity of the metal. Assume that the specific heat capacity of water is :- \rm \: 4.2 \: Joule \: g^{ - 1} \: K ^{ - 1}4.2Jouleg−1K−1
Answers
Answer:
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here izz ur answer
Mass if the solid , m
Mass if the solid , m s=50g
=50gInitial temperature of the solid, t
=50gInitial temperature of the solid, t s=1500
=50gInitial temperature of the solid, t s=1500C=150+273=423k
=50gInitial temperature of the solid, t s=1500C=150+273=423kMass of water, m
=50gInitial temperature of the solid, t s=1500C=150+273=423kMass of water, m w=100g
=100gTemperature of the water, tw=110C=11+273=293k
C=11+273=293kAccording to principle of calorie meter,
C=11+273=293kAccording to principle of calorie meter,Heat gained by water =Heat lost by the solid
C=11+273=293kAccording to principle of calorie meter,Heat gained by water =Heat lost by the solid ∴mw
Cw
Cw(t−t w)=m s
Cs (ts−t)⇒100×4.2(293−284)=50×Cs×(423−293)⇒3780=6500Cs
∴Cs =0.582J/gk
Answer:
in 100 g of water at 11°C. The final temperature is 20°C. Calculate the specific heat capacity of the metal. Assume that the specific heat capacity of water is :- \rm \: 4.2 \: Joule \: g^{ - 1} \: K ^{ - 1}4.2Jouleg−1K−1
Explanation:
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