mass of 50% pure H2SO4 required to neutralise 4kg of NaOH
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2.25 kilograms of Sulfuric acid.
80g NaOH = 98g,100% H2SO4
4000g NaOH = 4900g, 100% H2SO4.
hence for 50% the mass is 2.25Kg
80g NaOH = 98g,100% H2SO4
4000g NaOH = 4900g, 100% H2SO4.
hence for 50% the mass is 2.25Kg
AbhilipsaDas:
how full process
40g NaOH neutralizes 98grams of H2SO4. 4000grams NaOH neutralizes 9800 grams of H2SO4. Now 9.8Kg of 100% H2SO4 is required, hence for 50% the mass is 4.9Kg
ok thanks
but in balanced reaction its not working
2mol NaOH equivalent to 1mol H2SO4 will do the trick.
H2SO4 +2 NaOH - > Na2SO4+H2O
i really can't understand
edited the answer
that means the answer is 4.9
2.25Kg, for some reason I thought about sodium bi carbonate in the first place. Sorry about that.
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It required 2.25 kg mass
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