Question

Mass of a ball is 70g its velocity is 0.5m/s is stoped by a player in 0.5 s what is force applied by the player to stop the ball

Answer 1

u = 0.5 m/s
v = 0 m/s ( because ball stops)
t = 0.5 s
$a \: = \frac{v - u}{t} \\ a = \frac{0 - 0.5}{0.5} = \frac{ - 0.5}{0.5} = - 1 \: \frac{m}{ {s}^{2} }$
F = ma
$= 70 \: g \times ( - 1) \: \frac{m}{ {s}^{2} } \\ = 0.07 \: kg \times ( - 1) \frac{m}{ {s}^{2} } \\ = - 0.07 \: newtons$
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