Mass of a body doubles and velocity increases by three times then its kinetic energy
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let initial mass be 'm'
and velocity be 'v'
so KE1=1/2mv^2
now mass become='2m'
velocity become='3v'
now KE2=1/2(2m)(3v)^2
KE2=9mv^2
so KE INCREASED BY 18 TIMES
and velocity be 'v'
so KE1=1/2mv^2
now mass become='2m'
velocity become='3v'
now KE2=1/2(2m)(3v)^2
KE2=9mv^2
so KE INCREASED BY 18 TIMES
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mass of a bpdy doubles and velocity increased by three times then its kinetic energy increased 18 times
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