Question

Mass of a body is doubled. How does its acceleration change under given force ?
(please answer my question ​

Answer 1

Answer

New acceleration will be half of original acceleration

Given

Mass of a body is doubled

To Find

How does its acceleration change under given force

Formula Applied

$\bf{\red{F=ma\ \; \bigstar}}$

Solution

Force for a body of mass , m with acceleration a is given by ,

$\to\ \rm F=ma\\\\\to\ \rm a=\dfrac{F}{m}\ ...(1)$

When mass of a body is doubled , we need to find how acceleration changes under given force ,

⇒ m' = 2m

⇒ a' = ?

⇒ F' = F

Since , same force acting

Apply formula ,

$\to\ \rm F=ma\\\\\to\ \rm F'=m'a'\\\\\to\ \rm (F)=(2m)a'\\\\\to\ \rm F=2a'm\\\\\to\ \rm a'=\dfrac{1}{2}\bigg(\dfrac{F}{m}\bigg)\\\\\to\ \rm a'=\dfrac{1}{2}(a)\ [\; From\ (1)\ ]\\\\\rm \to\ a'=\dfrac{a}{2}\ \; \bigstar$

So , new acceleration will be half of original acceleration

Answer 2

Answer:

New acceleration will be half of original acceleration

Given-

Mass of a body is doubled

To Find-

How does its acceleration change under given force

Formula Applied-

F=ma

Solution-

Force for a body of mass , m with acceleration a is given by ,

F = ma

a = F/m....(1)

When mass of a body is doubled , we need to find how acceleration changes under given force ,

⇒ m' = 2m

⇒ a' = ?

⇒ F' = F

Since , same force acting

Apply formula ,

F = ma

F' = m'a'

(F) =(2m)a'

F = 2a'm

a' = 1/2(F/m)

a' = 1/2(a) [from (1)]

a' = a/2

So , new acceleration will be half of original acceleration

Explanation:

hope it helps