mass of a body is increased by 2 times and velocity is decreased by 3 time. find the ratio of its initial and new kinetic energy
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Answer:
let initial velocity be 'v'
and initial mass of the body be 'm'
Then Initial kinetic energy =mv²/2
final kinetic energy when mass is 2m, velocity is v/3
=2m(v/3)²/2
=mv²/9
therefore (initial KE)/(final KE)= mv²/2/mv²/9
= 9/2
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