Mass of a car is 1000kg.If its speed increase from 36km/hr to 72 km/hr then find gain in its Kinetic energy?
Answers
Answered by
1
mass=1000 kg
u=36 km/hr=36×5/18=10m/s
v=72 km/hr=72×5/18=20m/s
work done,
W=increase in kinetic energy
=1/2×mv^2-1/2×mu^2
=1/2m(v^2-u^2)
=1/2×1000×(20^2-10^2)
=500×300
=150000 J
87500is the gain in kinetic energy
u=36 km/hr=36×5/18=10m/s
v=72 km/hr=72×5/18=20m/s
work done,
W=increase in kinetic energy
=1/2×mv^2-1/2×mu^2
=1/2m(v^2-u^2)
=1/2×1000×(20^2-10^2)
=500×300
=150000 J
87500is the gain in kinetic energy
Answered by
0
72 kmph = 72 × 5/18 m/s = 20 m/s
36 kmph = 36 × 5/18 m/s = 10 m/s
Increase in kinetic energy = 0.5 m (v² - u²)
= 0.5 × 1000 kg × [(20 m/s)² - (10 m/s)²]
= 150 × 10³ J
= 150 kJ
Increase in its kinetic energy is 150 kJ
36 kmph = 36 × 5/18 m/s = 10 m/s
Increase in kinetic energy = 0.5 m (v² - u²)
= 0.5 × 1000 kg × [(20 m/s)² - (10 m/s)²]
= 150 × 10³ J
= 150 kJ
Increase in its kinetic energy is 150 kJ
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