Question

mass of A is 2 m and of B is 4m .force Fis applied on A in given direction. What is the acceleration of blockB? ​

Answer 1

Answer:

Static friction is a self-adjusting force.

The limiting value of friction up to which the body stays at rest till it starts moving is given by, F  

s

​  

=μmg

where μ is the coefficient of static friction.

Below that limit, the frictional force is equal to the force applied.

Here F  

s

​  

=0.8×4×10=32N ;   g=10m/s  

2

 

Whereas force applied is 19N less than the limiting value of friction.

Hence Frictional force is 19N.  

Explanation:

Answer 2

Answer:

The acceleration is F/6m

Please refer to the attachment. Hope, it helps you.