mass of a photon of wavelength lambda is given by
Answers
Answered by
3
heyy dear samreen ur answer.......
lamda = 3.6 angstrom = 3.6 x 10^-10 mvelocity of photon = velocity of light m = h/lamda*v ( from de-brogile’s equation)m = 6.626 x 10^-34/3.6 x10^-10 x 3 x 10^8m = 6.626 x 10^-32/10.8m = 0.6135 x 10^-32m = 6.135 x 10^-33 kg...........
hope it will help u................@kundan
lamda = 3.6 angstrom = 3.6 x 10^-10 mvelocity of photon = velocity of light m = h/lamda*v ( from de-brogile’s equation)m = 6.626 x 10^-34/3.6 x10^-10 x 3 x 10^8m = 6.626 x 10^-32/10.8m = 0.6135 x 10^-32m = 6.135 x 10^-33 kg...........
hope it will help u................@kundan
Answered by
2
Answer:
Momentum=p
p=h/lambda=mass*velocity
mass=h/(lambda*velocity)
mass=6.63*10^(-34)/(3. 6*10^(-10)*3*10^(8))
mass=0.613888*10^(-32)kg
mass=6.13888*10^(-33)kg
Similar questions
Social Sciences,
9 months ago
Math,
9 months ago
English,
9 months ago
Math,
1 year ago
Math,
1 year ago