Mass of a planet is M. If the mass of the planet is reduced to 1/8th of the original without change in density. Then what is the new value of acceleration due to gravity of the planet.
a) 5g
b) g/2
c) 3g
d) g/3
Please experts.... answer it fast clear and with statements... then I will mark that answer as the brainliest answer
Answers
Answered by
4
acceleration due to gravity becomes twice of original.
formula for acceleration due to gravity is

G is a constant equal to 6.67 × 10-11 N-m2/kg2,
M is mass of planet which is also a constant
r is radius of planet which is also a constant
if mass and radius are half of original i.e M/2 and r/2
g'=G(M/2)/(r/2)^2
which gives g' = 2GM/r^2
g'=2g
acceleration due to gravity got twice of original
formula for acceleration due to gravity is

G is a constant equal to 6.67 × 10-11 N-m2/kg2,
M is mass of planet which is also a constant
r is radius of planet which is also a constant
if mass and radius are half of original i.e M/2 and r/2
g'=G(M/2)/(r/2)^2
which gives g' = 2GM/r^2
g'=2g
acceleration due to gravity got twice of original
jsaidisha:
why r will be r/2
hi answer is wrong
no its ryt
no its wrng
ryt ans is g/2
Answered by
1
acceleration due to gravity become 2 times of orginal
formula for acceleration due to gravity is above
G is constant equal to 6.67×10^-11Nm^2kg^-2
if m is M/2
r is r/2
g'=G(M/2)/(r/2)^2
which gives g'=2GM/r^2
g'=2g
acceleration due to gravity become 2 times of orginal
formula for acceleration due to gravity is above
G is constant equal to 6.67×10^-11Nm^2kg^-2
if m is M/2
r is r/2
g'=G(M/2)/(r/2)^2
which gives g'=2GM/r^2
g'=2g
acceleration due to gravity become 2 times of orginal
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