Question

Mass of a rectangular bar of an iron piece is 320g. Its dimensions are 2x2x10cm3. What is its specific gravity? Will the bar float or sink in water?
please explain with steps

Answer 1

Answer:

Relative density is also called as specific gravity. It is the ratio of the density of a substance to the density of water (i.e. 1 g per cubic centimetre).

∴ Sp. Gravity of iron = Density of Iron/Density of Water

Density of Iron = mass / volume = 320g/(2 × 2 × 10 cm3) = 320 / 40 = 8 g/cm3

Density of water = 1 g/cm3

∴ Sp. Gravity of iron = 8/1 = 8

Since the density of the bar is more than the density of water, the bar will sink.

Explanation:

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Answer 2

Given:

Mass of bar = 320 gram and dimensions are 2 × 2 × 10 cm³.

To find:

• Specific gravity?

Calculation:

• Specific gravity is otherwise known as the density of the substance.

• It is calculated as the ratio of mass and volume of a substance.

$\therefore \: density = \dfrac{mass}{volume}$

$\implies \: density = \dfrac{320}{2 \times 2 \times 10}$

$\implies \: density = \dfrac{320}{40}$

$\implies \: density = 8 \: g/ {cm}^{3}$

So, specific gravity is 8 g/cm³.

• Now, specific gravity of the substance (8 g/cm³) is higher than that of water (1 g/cm³). So, it will sink down.