Question

mass% of an aquous Sol is 20% calculate the amount of solute present on 1 kg solution​

Answer 1

Answer:

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Answer 2

Answer:

$\frac{w}{w}\% = 20 \\ 100gm \: solution \: has \: 20gm \: kl \\ 80gm \: solvent \: has \: 20 \: gm \: kl \\ m = \frac{20 \frac{166}{80} }{1000} = \frac{20 \times 1000}{166 \times 80} = 1.506 \\ 1.506 \: \frac{mol}{kg}$

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