Mass of an electric wire of diameter 4mm has mass 3.52 kg . Density of the material of
the wire is 7 *10^3
kg/ m^3
. If resistivity of the wire is 3.45*10^-6 ohm*m , then find the
resistance of the wire.
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Answer:
11.02×10^(12) ohms.
Explanation:
Radius = 2mm = 0.002 m
Area = πr² = π×4×10^(-6) m²
Mass = 3.52kg
Density=7000 kg/m³
Volume = mass/density = 3.52/7000 =
Area × length = 3.52/7000
Length = 3.52/[7000×π×4×10^(-6)]
=0.126×10³
= 126/π m
Resistance = resistivity × length/area
= 3.45×10^(-6) × (126/π)÷[π×4×10^(-6)]
=[(434.7×10^6)/π]÷[π×4×10^(-6)]
=108.675×10^(12) ÷π²
=11.02×10^(12) ohms.
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