Mass of C present in 684g of sucrose (C*12H*22O*11) is
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Answer:
Explanation:
The balanced chemical reaction is 24C(s)+22H
2
(g)+11O
2
(g)→2C
12
H
22
O
11
(s).
The number of moles of carbon, hydrogen and oxygen present are
12
84
=7,
2
12
=6 and
22.4
56
=2.5 moles respectively.
Oxygen is the limiting reagent.
The mass of sucrose present is 2.5×
11
2
×342=155.5 g.
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