Chemistry, asked by abbasali6472, 10 months ago

Mass of cane sugar required to prepare 250g of 20%(w/w) solution is

Answers

Answered by Anonymous
214

\huge\underline{\underline{\bf \green{Answer-}}}

Mass of cane sugar required to prepare 250g of 20%(w/w) solution is ⎯

\huge\underline{\underline{\bf \green{Solution-}}}

\large\underline{\underline{\sf Given:}}

  • Mass percent ( mass % ) = 20%
  • Mass of Solution = 250 g

\large\underline{\underline{\sf To\:Find:}}

  • Mass of sugarcane

\large{\boxed{\bf \blue{Mass\%=\dfrac{Mass\:of\:Solute}{Mass\:of\: Solution}×100}}}

\implies{\sf 20=\dfrac{Mass\:of\:sugarcane}{250}×100 }

\implies{\sf Mass\:of\:sugarcane=\dfrac{20×250}{100} }

\implies{\sf  \dfrac{5000}{100}}

\implies{\bf \red{Mass\:of\:Sugarcane=50\:g} }

\huge\underline{\underline{\bf \green{Answer-}}}

Mass of sugarcane is {\bf \red{50\:g}}

Answered by jacob909
0

Answer:

Mass of sugarcane is 50gm.

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