Question

mass of carbon in 3.38gram of CO2​

Answer 1

Answer:

CxHy + O2 ==> CO2 + H2O

moles of C: 3.38 g CO2 x 1 mole CO2/44 g x 1 mole C/mole CO2 = 0.0768 moles C

moles of H: 0.690 g H2O x 1 mole H2O/18 g x 2 moles H/mole H2O = 0.0767 moles H

Since the mole ratio of C:H is 1:1, the empirical formula is CH

10.0 L x 1 mole/22.4 L = 0.446 moles

11.6 g/0.446 moles = 26.0 g/mole = molar mass of the gas

Molar mass of empirical formula = 12 + 1 = 13

26.0 g/13 g = 2

Molecular formula = C2H2 (acetylene)