Question

Mass of first object is reduced 3 times mass of second object is increased 4 times and distance between them is reduced 3 times​

Answer 1

Given,

Distance increased twice.

Gravitational force,F=GM

r

2

m

where m and r is variable.

If r increase to twice, keeping F= constant.

F=GM

(2r)

2

m

′

GM

r

2

m

=GM

4r

2

m

′

m

′

=4m

Hence, one mass increase to four times.

Answer 2

Explanation:

mass of 1st object =M

new mass = M/3

mass of 2nd object = m

new mass = 4m

distance between them = x

new distance = x/3