Question

mass of hydrogen gas liberated when 36g of mg completely reacts with hcl is​

Answer 1

Explanation:

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Answer 2

Given: 36 grams of Mg(Magnesium) completely reacts with HCl( Hydrochloric acid)

To find: Mass of hydrogen gas evolved

Explanation: Reaction between Mg and HCl can be represented by the below equation:

Mg + 2 HCl ----> MgCl2 + H2

Here, 1 mole of Mg reacts with HCl completely to form 1 mole of H2.

Given mass of Mg that reacted= 36 g

Molar mass of Mg= 24 g

Moles of Mg reacted

= Given mass/ Molar mass of Mg

= 36/24

= 3/2

= 1.5 moles

1.5 moles of Mg reacts with HCl to produce 1.5 moles of H2.

Molar mass of H2 = 2 g/mol

Mass of H2 produced

= Number of moles * Molar mass of H2

= 1.5 * 2

= 3 grams

Therefore, 3 grams of hydrogen gas is liberated when 36 grams of Mg reacts with HCl completely.