Question

mass of moles of O2 formed ?
mass of moles of Pb(NO3)2 in the sample
Mass of one mole of Pb(NO3)2=331g
Mass of lead(ii) nitrate in the sample
percentage of lead (ii) nitrate in the sample​

Answer 1

Answer:

33.1 grams

Explanation:

let x g mass of lead nitrate is required

mole of lead nitrate =

331

x

then according to question

molarity =

volume of solution

mole of solute

1M =

331

x

×10

x=33.1grams