Question

Mass of NaOH present per dm^3 of 0.25 M NaOH solution is​

Correct answer mark brainlist and wrong answer reported.

Answer 1

Answer:10 g

Explanation:

Molar mass * 0.25

Answer 2

Given,

In $NaOH$ solution,

Molarity, $M=0.25M$ per $dm^{3}$

To find,

Mass of $NaOH$, $m$.

Solution,

We know that,

Molarity of a solution, $M= \frac{moles of solute}{volume of solution(L)}$

⇒$0.25M=\frac{0.25moles}{1L}$

Number of moles of $NaOH, n=0.25$.

Now,

We know that,

Mass(m) = moles(n) × molar mass(X)

And,

Molar mass of $NaOH, X=40g/mol$

⇒$m=0.25mol$×$40g/mol$

⇒$m=10g$

Therefore, the  mass of $NaOH$ solution is $10g$.