mass of nitrogen present in 4.6 g of no2 is (atomic mass of n= 14 u and o=16 u is a) 2.8gm b) 2.2g c) 1.8g d) 1.4g
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Given:
Given mass of NO₂ is 4.6g
To find:
Mass of nitrogen present in 4.6g of NO₂
Solution:
Molecular mass of NO₂ = Atomic mass of N + (2×Atomic mass of O)
= 14+(2×16) = 46u
Firstly we have to find the number of moles,
Number of moles = given mass/molecular mass
here, given mass is 4.6g
molecular mass is 46u
so, no. of moles = 4.6/46
= 0.1moles
now, Mass of nitrogen in 1 mole of NO₂ is = 14g
Mass of nitrogen in 0.1 mole of NO₂ is = 0.1×14g
= 1.4g
The mass of nitrogen present in 4.6g of NO₂ is 1.4g.
So, Option (d) is correct.
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