Mass of non-volatile solute with molecular mass 60, which
is dissolved in 100 g of heptane to decrease the vapour
pressure to 90%
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Answer:
Given that P
o
=100,P=25,M=60,W=100,MH
2
O=18 .
⇒
P
o
P
o
−P
=
m
W
×
W
M
⇒
100
100−25
=
60
W
×
100
18
W=250gm
Molality=
Weight of solvent
Mole of solute
=
60×1000
250×1000
=41.66m .
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