Mass of oxygen in one mole each of Fe2O3 and FeO is in the simple ratio of
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Answer:
the ratio is 3: 1
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Weight of oxygen in one mole each of Fe₂O₃ and FeO is in the simple ratio of 3 : 1
Explanation:
One mole of Fe₂O₃ means 160 gram of Fe2O3
In 160 gram of Fe₂O₃ , weight of Oxygen = 16 × 3 = 48
Also, one mole of FeO means 72 gram of FeO
In 72 gram of FeO, weight of Oxygen = 16
Thus, the ratio of weight of Oxygen in Fe₂O₃ and FeO
= 48/16
= 3/1
= 3 : 1
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Q: Equal mass of Fe2O3 and FeO has the mass of oxygen in the ratio:
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