Mass of oxygen required to burn 12 grams of magnesium?
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Answer:
2Mg+ O2 = 2MgO2
2vol of mg= 12g
1vol of = 6g
Mass required to burn = 6g of oxygen
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2Mg + O² --------> 2MgO
2 moles Mg needs 1 mole O²
1 mole Mg needs ½ mole O²
No: of moles of Mg in 12g = Given mass/Molar mass
= 12/12 = 1 mole
Therefore,
½ mole of O² = Given mass/Molar mass
Given mass = ½×16 = 8g
Therefore, 12g Mg needs 8g of O² to burn
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