mass of particle is 0.5kg ,it is moving initially with a speed of 80m/s towards east.at t=0 , when particle is at x=0,a force of 20N directed towards west is being applied on it for 4sec , it's position after 5sec is?
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Mass of particle is 0.5kg ,it is moving initially with a speed of 80m/s towards east.at t=0 , when particle is… ... when particle is at x=0,a force of 20N directed towards west is being applied on it for 4sec , it's position after 5sec is?
Explanation:
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Answer:
-80m
Explanation:
initially the particle is moving towards east with velocity 80 metre per second and the force is in opposite direction so it provides retardation.
a=F/m
a= -40m/s^2 towards west
this acceleration is applied only for four seconds so final velocity is
v=u + at
v= 80+ (-40)*4
v= -80m/s towards west
now there is no acceleration after 4 seconds
so
s= speed*time
s= -80*1 = -80m i.e. along -x axis or towards west
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