Question

mass of the moon is 7.34 ×10^22 kg and radius is 1.74×10^6 m . the gravitational field strength at its surface is

Answer 1

Answer:

The radius of the moon is 1.74 x 106 m. The mass of the moon is 7.35 x 1022 kg. Find the acceleration due to gravity on the surface of the moon. The acceleration due to gravity on the surface of the moon is 1.620 m/s2.

Answer 2

Answer:

The gravitational field strength of moon at its surface is 1.617N/kg

Explanation:

Given that,

The mass of moon is

$7.34 \times 10 {}^{22} kg$

The radius of moon is

$1.74 \times 10 {}^{6} m$

We are required to find the gravitational field strength.It is given by the relation

$g = \frac{GM}{R {}^{2} }$

Here G is the gravitational constant and its value is

$G = 6.67 \times 10 {}^{ - 11} N m {}^{2} kg {}^{ - 2}$

Now substituting the known values in above relation,we get

$g = \frac{6.67 \times 10 {}^{ - 11} \times 7.34 \times 10 {}^{22} }{(1.74 \times 10 {}^{6} ) {}^{2} } \\ = > g = 1.617Nkg {}^{ - 1}$

Therefore,The gravitational field strength of moon at its surface is 1.617N/kg

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