mass of the solution of 1 molal glucose solution to get 0.2 mole of glucose is
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Answer:
236g
Explanation:
m = no of moles of solute/mass of solvent (inKg)
n = 0.2
0.2 = m(g)/180 [Molar mass of glucose = 180g/mol]
m(g) = 36g = mass of glucose
m = 0.2/k
1 = 0.2/k
k = 0.2Kg = 200g = mass of solvent
mass of solution = mass of solvent + mass of solute(glucose)
= 200+36 =236g
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