Question

mass of the sun is 2x10^30kg and the mass of the earth is 6x10^24kg . If the average distance between the sun and the earth be 1.5x10^8km, calculate the force of gravitation between them. (G = 6.7×10^-11nm²/kg²)​

Answer 1

Given:-

$mass \: of \: sun \: (m) = 2 \times 10 {}^{30} kg$

$mass \: of \: earth( m.) = 6 \times 10 {}^{24} kg$

$distance \: between \: earth \: and \: sun = 1.5 \times 10 {}^{11} m$

$gravitational \: constant = 6.7 \times 10 {}^{ - 11} nm {}^{2}per kg {}^{2}$

To Find:-

• Gravitational force between them (F).

Solution:-

By using this formula

⟹ F = Gm×m./d²

Put the value which is given above

F=6.7×10^-11×2×10^30×6×10^24(6.7×10^-1)²

By solving we get the final answer

⟹F = 35.57×10^21 N.

Additional Information!!

✧ The universal law of gravitation state that the gravitational force of attraction between any two particle is directly proportional to the product of masses of the particles and is inversely proportional to the square of the distance between the particles.

✧

✧ Product of mass and acceleration is called force.

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀OR

A push or pull of an object is called force.

✧ SI unit of Force is Newton.

✧ It is denoted by N.

✧ Force is vector Quantity i.e., both Magnitude and direction.

✧ Mathematical term

⟹ Force = Mass×Acceleration

Answer 2

Given :

$M_1$ =mass of sun=$2×{10}^{30}\:kg$

$M_2$=mass of earth=$6×{10}^{24}\:kg$

R= Avg. distance between the Earth and the Sun $=1.5×{10}^{11}\:m$

$G=6.7×{10}^{-11}\:N{m}^{2}/{kg}^{2}$

According to universal law of gravitation,

$\begin{gathered}F=\frac{G×M_1×M_2}{{r}^{2}}\\\\=\frac{6.7×{10}^{-11}×2×{10}^{30}×6×{10}^{24}}{{(1.5×{10}^{11})}^{2}}\\\\\\\underline{F=3.57×{10}^{22}\:N}\\\\\\\underline{\boxed{\sf{ F=3.57×{10}^{22}\:N}}} \end{gathered}$

#CARRYONLEARNING