mass of the water filled in a frustrum of 11 cm h r1= 4.5 cm r2= 7.5 cm ?
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mass of the water filled in a frustrum of 11 cm h r1= 4.5 cm r2= 7.5 cm ?
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Substituting the value of H + h in the formula for the volume of frustum we get = 1/3 π [R2 (Rh/r) – r2 h] = 1/3 π [R3h/r – r2 h] =1/3 π h (R3/r – r2) = 1/3 π h (R3 – r3/r) The Volume of Frustum of Cone: 1/3 π h [(R3 – r3)/r].
by this formula you can find your answer ✔️✔️
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