Question

Mass percent of urea (MW = 60) in an aqueous solution is 10% (w/w) then molality of solution will

be:​

Answer 1

Answer:

1.844m

Explanation:

in 100g solution there will be 10g solute present

mass of urea is 10g

molar mass of urea=60g/mol

moles of urea=mass/molar mass

=10/60=1/6mol of urea=0.166mol

so total mass is 100g,mass of solute=10g

mass of solvent 100-10=90g=90/1000kg

molality=moles of solute/mass of solvent in kg

=0.166/90/1000

=1.844m