Question

Mass percentage of magnesium in an enzyme is 0.04% the minimum molecular weight of the enzyme is

Answer 1

Answer:

1.66666666 x 10^-5

Explanation:

formula=

wt.of element /wt.of compound x100

0.04=24/mass of enzyme x100

0.04/100 x 24

Answer 2

The minimum molecular weight of the enzyme is 60,000 amu.

Given,

Mass percentage of magnesium in the enzyme=0.04%.

To find,

the minimum molecular weight of the enzyme.

Solution:

To find the minimum molecular weight of the enzyme, we need to assume that it contains only one atom of magnesium.

Let the mass of the enzyme be $x$ $amu$.

0.04% magnesium in the enzyme means 0.04 g of magnesium in 100 g of enzyme.

(Mass of magnesium/Mass of enzyme)x100=0.04%

Mass of magnesium=24 amu.

$\frac{24}{x}X100=0.04\\\frac{24}{x}=\frac{0.04}{100} \\\frac{24}{x}=0.0004\\x=\frac{24}{0.0004} \\x=60000 amu.$

The minimum molecular weight of the enzyme can be 60,000 amu.

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