Question

Mass percentage of oxygen in NaOH molecule is 'X' and mass percentage of nitrogen in Mg, N2 is 'y'. The value of xxy 70 is​

Answer 1

Answer:

Nitric acid HNO

3

- mol wt. =1+14+48

=63 g

Mass percentage of hydrogen =

63

1

×100=1.586%

Mass percentage of nitrogen =

63

14

×100=22.22%

Mass percentage of oxygen =

63

48

×100=76.19%

Hence the percentage of H,Nand O are 1.58%,22.22% and 76.19% respectively.

I think this is your answer