Question

Mass percentage of Zn2+ in an enzyme is 0.2%. The minimum molecular weight of the enzyme is (Atomic wt. of Zn = 65.4)
0 16000 u
0 32700 u
0 24600
54200 u​

Answer 1

Answer:

Ans is 32700 see from attachment

Direct formula

Answer 2

Answer:

The enzyme's molecular weight measured is $32700 u$.

Therefore, option b) $32700u$ is the correct option.

Explanation:

The mass percentage of $Zn^{2+}$ in an enzyme = $0.2\%$

The molecular mass of $Zn$ = $65.4u$

The enzyme's molecular weight =?

As we know,

• The mass % in an enzyme can be calculated by the equation given below:
• Mass % = $\frac{Molecular weight of atom}{Molecular weight of enzyme} \times 100$

From this, we can calculate the molecular weight of the enzyme.

• The molecular weight of the enzyme = $\frac{Molecular weight of atom}{Mass\%} \times 100$

After putting the given values in the equation, we get:

• The enzyme's molecular weight = $\frac{65.4}{0.2}\times 100$ = $32700 u$.