Question

mass ratio of hydrogen sulphur and oxygen in sulphuric acid​

Answer 1

Given,

The main chemical compound is sulphuric acid or H2SO4.

To find,

The mass ratio of hydrogen, sulphur and oxygen in the main chemical compound.

Solution,

To calculate the mass ratio, we need to calculate the atomic mass of the individual elements.

Now, there are two hydrogen atoms. So, the atomic mass = 2 × 1 = 2

There is one sulphur atom.

So, the atomic mass = 32

There are four oxygen atoms.

So, the atomic mass = 4 × 16 = 64

Now, the final mass ratio

= Hydrogen : Sulphur : Oxygen

= 2 : 32 : 64

= 1 : 16 : 32

Hence, the mass ratio is 1:16:32

Answer 2

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

TO DETERMINE

The mass ratio of hydrogen sulphur and oxygen in Sulphuric Acid

CALCULATION

$\sf{H_2SO_4 \: \: contains}$

• 2 Hydrogen ( H ) atom

• 1 Sulphur atom ( S )

• 4 Oxygen atom ( O )

Now Molar masses of H = 1 , S = 32, O = 16

Molar mass of the compound ( Sulphuric Acid )

$= \sf{ \: (2 \times 1) +32 + (4 \times 16) }$

$= 98$

$\displaystyle \: \sf{ \: The \: ratio \: of \: Hydrogen \: in \: the \: compound \: = \frac{2}{98} } \:$

$\displaystyle \: \sf{ The \: ratio \: of \: Sulphur \: in \: the \: compound \: = \frac{32}{98} } \:$

$\displaystyle \: \sf{ \: The \: ratio \: of \: Oxygen \: in \: the \: compound \: = \frac{64}{98} } \:$

Hence the mass ratio of hydrogen sulphur and oxygen in Sulphuric Acid is

$= \displaystyle \sf{ \frac{2}{98} : \frac{32}{98} : \frac{64}{98} }$

$= \displaystyle \sf{2 : 32 : 64}$

$= \displaystyle \sf{1 :16 : 32}$