Question

Masses 8, 2, 4,2 kg are placed at the comers A, B, C, D respectively of a square ARCD) of diagonal
cm. The distance of centre of mass from A will be
(D) 10 om
(C) 40 cm
(D) 60 cm
(A) 20 cm

Answer 1

Explanation:

Center of mass is given by=

m

1

+m

2

+m

3

+m

4

(m

1

x

1

+m

2

x

2

+m

3

x

3

+m

4

x

4

)

The diagonal of a square is 0.8 meters

therefore using pythagoras law each side is of a distance 0.56 meters

So centre of mass

8+2+4+2

8×0×2×0.56+9×0.8+2×0.56

=0.32meter

=30cm

So (B) is correct answer