Question

masses 8,2,4,2 kg are placed at the corners a,b,c,d respectively of a square a,b,c,d of diagnol 80 cm . The distance of centre of mass from "a" will be????????? pls answer I will mark u as brainliest .....

Answer 1

at the half of the diagonal

Answer 2

Centre of mass is given by = (m1x1 +m2x2 +m3x3 +m4x4)/(m1+m2+m3+m4)

where m is the respective mass and x is the respective distance with respect to A ( in metres)

the diagonal of a square is 0.8 metres

therefore using pythogoras law each side is of a distance 0.56 metres.

therefore centre of mass is =

(8*0+2*0.56+4*0.8+2*0.56)/(8+2+4+2)=.34 metres from A

plz mark this in brainliest