Question

masses m and 3 cm are attached to the ends of spring of constant k if the system vibrates freely the period of oscillation will be

Answer 1

Explanation:

2π✓(m/k)

Here m is the equivalent Mass otlf the 2 masses and is given by 1/meq = 1/m1+ 1/m2 => meq = m*3m/4m = 3/4m

So times period of oscillation is 2π✓(3m/4k) = √(3m/k) * π