Question

Masses m1,m2 and m3 are connected light string as shown in figure. There is no friction at anywhere. Which is the F.B.D of mass m3​

Answer 1

Explanation:

Masses M1,M2 and M3 are connected by strings of negligible mass which pass over massless and frictionless pulleys P1 and P2 as shown in the figure. The ...

Answer 2

Answer:

Since, the masses are moving with constant velocity, there is no acceleration and hence no external force is acting on them.

Force balance:

For mass m

1

:

T

1

=m

1

g −−−−(i)

Formassm

3

T

2

=μm

3

g

T

2

=0.25×4×10

T

2

=10N

Formassm

2

:

T

1

=m

2

μgsinθ+m

2

gcosθ+T

2

T

1

=4×0.25×10×

5

3

+4×10×

5

4

+T

2

T

1

=6+32+10

T

1

=48N

Puttingin eqn(i)

48=m

1

×10

m

1

=4.8kg

Therefore,

The mass m

1

=4.8 kg and the tension in the horizontal spring T

2

=10N