masses of three wires of same metal are in the ratio 1 is to 2 is to 3 and their length in the ratio 3 is to 2 is to 1 . electrical resistance of these wires will be in ratio of :- (1)1:1:1 (2) 1:2:3 (3) 9:4:1 (4) 27:6:1
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8
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Explanation:
Assuming that the cross-sectional areas are not equal.
We know
R=ρlA
R=ρl2Al
R=ρl2V
Where V is the volume of each wire. Let d be the density.
d=mV⟹V=md
R=ρl2dm
Therefore,
R∝l2m
From the given ratios,
R1:R2:R3=521:323:125
R1:R2:R3=125:15:1
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26
Answer:
Explanation:follow this steps it may helps u ty.
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