Question

masses of three wires of same metal are in the ratio 1 is to 2 is to 3 and their length in the ratio 3 is to 2 is to 1 . electrical resistance of these wires will be in ratio of :- (1)1:1:1 (2) 1:2:3 (3) 9:4:1 (4) 27:6:1​

Answer 1

Answer:

Explanation:

Assuming that the cross-sectional areas are not equal.

We know

R=ρlA

R=ρl2Al

R=ρl2V

Where V is the volume of each wire. Let d be the density.

d=mV⟹V=md

R=ρl2dm

Therefore,

R∝l2m

From the given ratios,

R1:R2:R3=521:323:125

R1:R2:R3=125:15:1

Answer 2

Answer:

Explanation:follow this steps it may helps u ty.