Math, asked by PragyaTbia, 1 year ago

Match each of the set on the left in the roster form with the same set on the right described in set- builder form:
(i) {1, 2, 3, 6}
(ii) {2, 3}
(iii) {M,A,T,H,E,I,C,S}
(iv)[1, 2, 5, 7, 9}

(a) {x: x is a prime number and a divisor of 6}
(b) {x : x is an odd natural number less than 10}
(c) {x : x is natural number and divisor of 6}
(d) {x : x is a letter of the word MATHEMATICS}.

Answers

Answered by abhi178
12
(i) -----> (c)
explanation :- {1, 2, 3, 6} , we observed elements of given set is divisor of 6 and also all elements are natural numbers.so, {1, 2, 3, 6} = {x : x is natural number and divisor of 6}

(ii)----> (a)
explanation : divisors of 6 are : 1, 2, 3, 6. so, prime divisors of 6 are 2, 3
hence, {2, 3} = {x : x is a prime number and divisor of 6 }

(iii)-----> (d)
explanation :- M, A, T , H , E , I , C , S are letters of the word MATHEMATICS.
so, {M, A, T, H, E, I, C, S} = {x : x is a letter of word MATHEMATICS}

(iv)----->(b)
explanation :- all odd numbers less than 10 are 1, 3, 5, 7, 9 so, {1, 3, 5, 7, 9} = {x : x is an odd number less than 10}.
Answered by mysticd
3

Answer:


( i ) -------> ( c )


( ii ) -------> ( a )


( iii ) ------> ( d )


( iv ) -------> ( b )

Step-by-step explanation:


( i ) -----> ( c )


{ 1,2,3,6 } = { x:x is a natural number


and divisor of 6 }


( ii ) -------> ( a )


{ 2 ,3 } = { x:x is a prime number


and a divisor of 6 }


( iii ) ------> ( d )


{ M ,A,T,H,E,I,C,S } = { x:x is a


letter of the word MATHEMATICS }


( iv ) -------> ( b )


{ 1,3,5,7,9 } = { x:x is an odd


natural number less than 10 }


••••


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