match the column
1)am . an amn
2)(am)n am-n,m>n
3)am/an (ab)m
4) am bm a m+n
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We \: know \:that ,\\\boxed {n^{. i) a_{ m+n} = a+(m+n-1. ii) a_{m-n} = a+(m-n-1)d \: /* Add equation (1) and (2) , we get. LHS = a_ ...
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