Question

Match the column
4.
Column I
Column II
(A) y = 4sin(5x-4t)+3cos(4t-5x+70/6)
(p) Particles at every position are performing SHM
(B) y = 10cost-
330
sin(100) t-
380
(q) Equation of travelling wave
330
(C) y = 10sin(
2x-120t) +10cos(120t+2x)
(r) Equation of standing wave
(D) y=10sin(210x-120t) +8cos(118-59/307x)
(s) Equation of Beats​

Answer 1

Answer:

this match the column are find in maths book

Explanation:

I hope you i am right

Answer 2

Answer:

(A)⇒p,q, (B)⇒s, (C)⇒p,r, (D)⇒s.

Explanation:

Let's discuss the columns one by one.

(A) $y=4sin(5x-4t)+3cos(4t-5x+\frac{\pi}{6})$

It is the superposition of two coherent waves as their frequencies are the same, so their equivalent will be another traveling wave. So, (A) will be matched with (p) particles at every position are performing SHM-because this wave is the function of sin and cos. And (q) Equation of traveling wave

(B)$y=10cos(t-\frac{x}{330})sin(100)(t-\frac{x}{330})$

Let's check at any point say at x=0,y=(10cost)sin(100t) at any point amplitude is changing sinusoidally. So, this is the equation of beats. So, (B) will be matched with (s) Equation of beats.

(C)$y=10sin(2\pi x-120t)+10cos(120t+2\pi x)$

It is the superposition of two coherent waves traveling in opposite directions. It is a standing wave. So, (C) will be matched with (p) particles at every position are performing SHM-because this wave is the function of sin and cos. (r) Equation of standing wave.

(D) $y=10sin(2\pi x-120t)+8cos(118t-\frac{59}{30\pi x})$

It is the superposition of two waves whose frequencies are slightly different.i.e.ω₁=120 and ω₂=118. So, (D) will be matched with (s) Equation of beats.

Hence we  can summarise our answer as follows;

(A)⇒p,q,

(B)⇒s,

(C)⇒p,r,

(D)⇒s.