Question

match the equivalent expressions
y-0.32y y+0.32y y+2/5y y-2/5y


7/5y >>>>> BLANK
0.68y >>>>>BLANK
3/5y>>>>>BLANK
1.32y>>>>>BLANK


Please answer.

Answer 1

Answer:

This is half question please give me the full question I know this answer and please follow me

Answer 2

SOLUTION

GIVEN

The given expressions are

$\displaystyle \sf{1. \: \: \: ( \: y - 0.32y \: )}$

$\displaystyle \sf{2. \: \: \: ( \: y + 0.32y \: )}$

$\displaystyle \sf{3. \: \: \: \bigg( \: y + \frac{2}{5} y \bigg)}$

$\displaystyle \sf{4. \: \: \: \bigg( \: y - \frac{2}{5} y \bigg)}$

GIVEN OPTIONS ARE

$\displaystyle \sf{1. \: \: \: \frac{7}{5} y \: }$

$\displaystyle \sf{2. \: \: \: 0.68y}$

$\displaystyle \sf{3. \: \: \: \frac{3}{5} y \: }$

$\displaystyle \sf{4. \: \: \: 1.32y}$

EVALUATION

FIRST EXPRESSION

$\displaystyle \sf{ \: y - 0.32 y \: }$

$\displaystyle \sf{ = \: y (1 - 0.32) \: }$

$\displaystyle \sf{ = 0.68y \: }$

Hence the correct equivalent expression is

$\displaystyle \sf{2. \: \: \: 0.68y}$

SECOND EXPRESSION

$\displaystyle \sf{ \: y + 0.32 y \: }$

$= \displaystyle \sf{ \: y(1 + 0.32 ) \: }$

$\displaystyle \sf{ = 1.32y \: }$

Hence the correct equivalent expression is

$\displaystyle \sf{4. \: \: \: 1.32y}$

THIRD EXPRESSION

$\displaystyle \sf{ \bigg( \: y + \frac{2}{5} y \bigg)}$

$= \displaystyle \sf{ \bigg( 1 + \frac{2}{5} \bigg)y}$

$= \displaystyle \sf{ \bigg( \frac{5 + 2}{5} \bigg)y}$

$= \displaystyle \sf{ \frac{7}{5}y }$

Hence the correct equivalent expression is

$\displaystyle \sf{1. \: \: \: \frac{7}{5} y \: }$

FOURTH EXPRESSION

$\displaystyle \sf{ \bigg( \: y - \frac{2}{5} y \bigg)}$

$\displaystyle \sf{ = \bigg( 1 - \frac{2}{5} \bigg)y}$

$\displaystyle \sf{ = \bigg( \frac{5 - 2}{5} \bigg)y}$

$\displaystyle \sf{ = \frac{3}{5}y }$

Hence the correct equivalent expression is

$\displaystyle \sf{3. \: \: \: \frac{3}{5} y \: }$

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