Math, asked by subhasinikolishetty7, 8 months ago

Match the following. 5x1=5M

5 points

3, -9/2

5

8

equilateral

12

Isosceles

6

triangle formed by the points p(√2,√2),Q(-√2,-√2),R(-√6,√6) is

If the area of Δ formed by joining mid poitns of the sides of ΔABC is 2 sq.units, then area of ΔABC

The distance of the point (5, 6) from the y-axis is

The perimeter of a triangle with vertices (0, 4) (0, 0) and (3, 0) is

Find the value of K, so that the area of the triangle with vertices (1, -1), (-4, 2k) and (-k, -5) is 24 sq.units.

triangle formed by the points p(√2,√2),Q(-√2,-√2),R(-√6,√6) is

If the area of Δ formed by joining mid poitns of the sides of ΔABC is 2 sq.units, then area of ΔABC

The distance of the point (5, 6) from the y-axis is

The perimeter of a triangle with vertices (0, 4) (0, 0) and (3, 0) is

Find the value of K, so that the area of the triangle with vertices (1, -1), (-4, 2k) and (-k, -5) is 24 sq.units.

Answers

Answered by geen
2
  • i also have one question and it is

Match the following. 5x1=5M

5 points

3, -9/2

5

8

equilateral

12

Isosceles

6

triangle formed by the points p(√2,√2),Q(-√2,-√2),R(-√6,√6) is

If the area of Δ formed by joining mid poitns of the sides of ΔABC is 2 sq.units, then area of ΔABC

The distance of the point (5, 6) from the y-axis is

The perimeter of a triangle with vertices (0, 4) (0, 0) and (3, 0) is

Find the value of K, so that the area of the triangle with vertices (1, -1), (-4, 2k) and (-k, -5) is 24 sq.units.

triangle formed by the points p(√2,√2),Q(-√2,-√2),R(-√6,√6) is

If the area of Δ formed by joining mid poitns of the sides of ΔABC is 2 sq.units, then area of ΔABC

The distance of the point (5, 6) from the y-axis is

The perimeter of a triangle with vertices (0, 4) (0, 0) and (3, 0) is

Find the value of K, so that the area of the triangle with vertices

Similar questions