Question

Match the following.
Material. Property
1) Tungsten. p) Alloy
2)Nicrome q) Semiconductor
3) Germanium. R) Metal.
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Answer 1

Explanation:

$Answer:</p><p></p><p>\begin{gathered}\blue{Let \: p \: be \: the \: number. }\\\blue{\underline{Suppose,}} \\\blue{ p÷4=q,remainder=2 }\\ \blue{q÷5=r, remainder=3} \\ \blue{r÷6=s, remainder=4 }\\ \blue{Then,} \\ \blue{r=6s+4} \\ \blue{q=5r+3=5(6s+4)+3=30s+23 }\\ \blue{p=4q+2=4(30s+23)+2=120s+94} \\ \blue{Let \: us \: now \: assume \: that \: the \: remainder \: s=1. }\\\blue{ Then \: we \: have: }\\\blue{ p=(120×1)+94=214 }\\ \blue{Hence, \: the \: number \: is 214} \\ \\ \red{\mathfrak{\underline{\large{Hope \: It \: Helps \: You }}}} \\ \green{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}\end{gathered}Letpbethenumber.Suppose,p÷4=q,remainder=2q÷5=r,remainder=3r÷6=s,remainder=4Then,r=6s+4q=5r+3=5(6s+4)+3=30s+23p=4q+2=4(30s+23)+2=120s+94Letusnowassumethattheremainders=1.Thenwehave:p=(120×1)+94=214Hence,thenumberis 214HopeItHelpsYouMarkMeBrainliest</p><p></p><p>$

Answer 2

1.metal

2.Alloy

3.semiconductor