Question

Match the following with correct response.  (1) Speed (A) Displacement / Time taken (2) Velocity.  . (B) Total distance covered / Total time taken  (3) Acceleration.  . (C) Change in velocity / Time taken (4) Average speed. (D)Distance covered / Time taken​

Answer 1

Answer:

Question:

$\begin{gathered}\boxed{\begin{array}{c|c}\\ \bf Column \: A & \bf Column \: B \\ \\ \sf 1. \: Speed & \sf \dfrac{Displacement}{Time \: taken} \\ \\ \sf 2. \: Velocity & \sf \dfrac{Total \: distance \: covered}{Total \: time \: taken} \\ \\ \sf 3. \: Acceleration & \sf \dfrac{Change \: in \: velocity}{Time \: taken} \\ \\ \sf 4. \: Average \: speed & \sf \dfrac{Distance \: covered}{Time \: taken} \end{array}}\end{gathered}$

Answer:

$\begin{gathered}\boxed{\begin{array}{c|c}\\ \bf Column \: A & \bf Column \: B \\ \\ \sf 1. \: Speed & \sf \dfrac{Distance \: covered}{Time \: taken} \\ \\ \sf 2. \: Velocity & \sf \dfrac{Displacement}{Time \: taken} \\ \\ \sf 3. \: Acceleration & \sf \dfrac{Change \: in \: velocity}{Time \: taken} \\ \\ \sf 4. \: Average \: speed & \sf \dfrac{Total \: distance \: covered}{Total \: time \: taken} \end{array}}\end{gathered}$

Additional information:

Difference between distance and displacement is mentioned:

$\begin{gathered}\boxed{\begin{array}{c|cc}\bf Distance&\bf Displacement\\\frac{\qquad \qquad \qquad\qquad\qquad \qquad\qquad\qquad}{}&\frac{\qquad \qquad \qquad\qquad\qquad \qquad\qquad\qquad}{}\\\sf Path \: of \: length \: from \: which &\sf The \: shortest \: distance \: between \\ \sf \: object \: is \: travelling \: called \: distance. &\sf \: the \: initial \: point \: \& \: final \\ &\sf point \: is \: called \: displacement. \\\\\sf It \: is \: scalar \: quantity. &\sf It \: is \: vector \: quantity \\\\\sf It \: is \: positive \: always &\sf It \: can \: be \: \pm \: \& \: 0 \: too \end{array}}\end{gathered}$

Difference between speed and velocity is mentioned:

$\begin{gathered}\boxed{\begin{array}{c|cc}\bf Speed&\bf Velocity\\\frac{\qquad \qquad \qquad\qquad\qquad \qquad\qquad\qquad}{}&\frac{\qquad \qquad \qquad\qquad\qquad \qquad\qquad\qquad}{}\\\sf The \: distance \: travelled \: by &\sf The \: distance \: travelled \: by \\ \sf \: a \: body \: per \: unit \: time&\sf \: a \: body \: per \: unit \: time \\ &\sf in \: a \: given \: direction \\\\\sf It \: is \: scalar \: quantity. &\sf It \: is \: vector \: quantity \\\\\sf It \: is \: positive \: always &\sf It \: can \: be \: \pm \: \& \: 0 \: too \\\\\sf Speed \: = \dfrac{Distance}{Time} &\sf Velocity \: = \dfrac{Displacement}{Time} \end{array}}\end{gathered}$

About acceleration:

$\begin{gathered}\boxed{\begin{array}{c}\\ \bf What \: is \: acceleration? \\ \\ \sf The \: rate \: of \: change \: of \: velocity \: of \: an \\ \sf object \: with \: respect \: to \: time \\ \sf is \: known \: as \: acceleration. \\ \\ \sf \star \: Negative \: acceleration \: is \: known \: as \: deceleration. \\ \sf \star \: Deceleration \: is \: known \: as \: retardation. \\ \sf \star \: It's \: SI \: unit \: is \: ms^{-2} \: or \: m/s^2 \\ \sf \star \: It \: may \: be \: \pm ve \: or \: 0 \: too \\ \sf \star \: It \: is \: a \: vector \: quantity \\ \\ \bf Conditions \: of \pm ve \: or \: 0 \: acceleration \\ \\ \sf \odot \: Positive \: acceleration: \: \sf When \: \bf{u} \: \sf is \: lower \: than \: \bf{v} \\ \sf \odot \: Negative \: acceleration: \: \sf When \: \bf{v} \: \sf is \: lower \: than \: \bf{u} \\ \sf \odot \: Zero \: acceleration: \: \sf When \: \bf{v} \: \sf and \: \bf{u} \: \sf are \: equal \end{array}}\end{gathered}$

Answer 2

Answer:

1. Speed - B) Total distance covered /

Total time taken

2. Velocity - A) Displacement /

Time taken

3. Acceleration - C) Change in velocity /

Time taken

4. Average speed - D) Displacement /

Change in time

Your one option is repeated.

D) Distance covered / Time taken - wrong

D) Displacement / Change in time - correct